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Many people find complex numbers disturbing. Before
delving into their mathematics, let’s consider why we might be interested
in these constructs.
Complex numbers act much like a bridge between two
villages that are located on opposite sides of a river. If the nearest
ford is 10 miles upstream, a bridge may provide a more direct path between
the two villages. In traveling between the two villages, we might take the
ford or the bridge. Either way, our destination is the same.
Similarly, we may have a mathematical problem that is
expressed entirely with real numbers and
has a solution that depends only on real numbers. However, using complex
numbers to reach that solution may provide a convenient shortcut compared
to techniques that only involve real numbers. We use the complex numbers
to bridge the gap between the problem and its solution. Doing so does not
change the solution. It merely provides a convenient means—a bridge—for
obtaining the solution.
The real numbers
contain no solution to the equation
.
We remedy this by extending the real numbers through the inclusion of an
“imaginary” number i that satisfies
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[1] |
As with any number, we can add, multiply, take roots and
perform other operations with this new number i. Multiplying i
by 5 results in the number 5i. Adding 3 to this yields 3 + 5i.
Squaring this yields 9 + 30i + 25i2.
At this point, our imaginary number may be starting to
seem like a Pandora’s box. By adding it to
,
we have actually added many numbers, and the expressions for these numbers
seem to be getting more and more complicated. What would happen now if we
were to divide our number 9 + 30i + 25i2 into 23?
In fact, such concerns are unfounded. Although the
addition of i to
does add many numbers to
,
expressions for these numbers always simplify to the form
where a and b are real. Using [1],
we can simplify our number 9 + 30i + 25i2 as
follows:
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9 + 30i + 25i2 = 9 + 30i
+ 25(–1) = –16 + 30i |
[3] |
which has the form [2].
We call the set of
numbers of the form [2] the
complex numbers and denote this set
.
Given a complex number z = a + bi, we call the real number
a the real part of z. We call the real number b the
imaginary part of z. This motivates the Re and Im
functions that map a complex number z = a + bi to its real
and imaginary parts a and b, respectively:
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Re(a + bi)
= a |
[4] |
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Im(a
+ bi) = b |
[5] |
If a complex number's real part a equals 0—so it
has the form bi for some real b—we say the number is purely
imaginary (or, more simly, imaginary).
Operations on complex numbers are extensions of the familiar operations
for real numbers. Indeed, we have already performed complex addition and
multiplication. We now formally define the operations of complex addition,
subtraction, multiplication, division, and the taking of square roots. Let
a + bi and c + di be complex numbers where a,b,c,d
.
Then
With the exception of 0, every real or complex number has
two square roots. For example, the square roots of 4 are 2 and –2. The
square roots of –1 are i and –i.
In [5] through [9], the formulas reduce to the
corresponding operations for real numbers if they are applied to real
numbers. Also, the right side of each formula is always defined and
corresponds to a complex number of the form [2]. The
only exception is division by zero, which is undefined with regard to real
as well as complex numbers.
Recall that we were motivated to introduce complex numbers
by the equation
,
which has no solution in
.
Is it possible that there is some equation that has no solution in
?
If this were the case, we might feel compelled to extend the complex
numbers through the addition of still another “imaginary” number to solve
this new equation. This will never happen, due to the
fundamental theorem of algebra.
Consider a polynomial equation of the form
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[10] |
where the
are constants. The theorem states that every such equation has exactly
n solutions z
(including repeated solutions).
We extend the exponential function to
with
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[11] |
This is the famous Euler’s
formula that links the exponential function with the sine and
cosine functions. We extend the sine and cosine functions to
with
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[12] |
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Express the following in a +
bi form: a. (5 + 3i )(2 – i
)
b. 5/(2 + i )
c. ei [solution] |
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Financial Math 3
This is the third in a series
of three-day courses on financial mathematics that take
participants from pre-calculus to stochastic calculus. Math
3 covers statistics, time series, stochastic calculus, and plenty of
financial applications. Math 3 is a fun, engaging, and enlightening
look at the fascinating field of financial math. |
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