Solution

Denote the matrix c. We first find its eigenvalues. These are values such that

(cI)v = 0 [3]

for some non-zero vector v. This is possible only if the determinant of (cI) is zero, a condition that yields the equation

2 – 5 + 4 = 0

[s1]

Solutions are = 1 and = 4. Substituting these into [3] and solving, we obtain corresponding eigenvectors

  and 

[s2]

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